1hello world and practice makes perfect and hello world again

1again and hello makes perfect practice world

1s = raw_input()
2words = [word for word in s.split(" ")]
3print " ".join(sorted(list(set(words))))

1word = input().split()
2
3for i in word:
4    if word.count(i) > 1:    #count function returns total repeatation of an element that is send as argument
5        word.remove(i)     # removes exactly one element per call
6
7word.sort()
8print(" ".join(word))

1word = input().split()
2[word.remove(i) for i in word if word.count(i) > 1 ]   # removal operation with comprehension method
3word.sort()
4print(" ".join(word))

1word = sorted(list(set(input().split())))              #  input string splits -> converting into set() to store unique
2                                                       #  element -> converting into list to be able to apply sort
3print(" ".join(word))

1'''Solution by: Sukanya-Mahapatra
2'''
3inp_string = input("Enter string: ").split()
4out_string = []
5for words in inp_string:
6    if words not in out_string:
7        out_string.append(words)
8print(" ".join(sorted(out_string)))

10100,0011,1010,1001

11010

1value = []
2items=[x for x in raw_input().split(',')]
3for p in items:
4    intp = int(p,2)
5    if not intp % 5:
6        value.append(p)
7
8print ','.join(value)

 1def check(x):                       # converts binary to integer & returns zero if divisible by 5
 2    total,pw = 0,1
 3    reversed(x)
 4
 5    for i in x:
 6        total+=pw * (ord(i) - 48)   # ord() function returns ASCII value
 7        pw*=2
 8    return total % 5
 9
10data = input().split(",")           # inputs taken here and splited in ',' position
11lst = []
12
13for i in data:
14    if check(i) == 0:               # if zero found it means divisible by zero and added to the list
15        lst.append(i)
16
17print(",".join(lst))

1def check(x):                   # check function returns true if divisible by 5
2    return int(x,2)%5 == 0      # int(x,b) takes x as string and b as base from which
3                                # it will be converted to decimal
4data = input().split(',')
5
6data = list(filter(check,data)) # in filter(func,object) function, elements are picked from 'data' if found True by 'check' function
7print(",".join(data))

1data = input().split(',')
2data = list(filter(lambda i:int(i,2)%5==0,data))    # lambda is an operator that helps to write function of one line
3print(",".join(data))

1'''Solution by: nikitaMogilev
2'''
3data = input().split(',')
4data = [num for num in data if int(num, 2) % 5 == 0]
5print(','.join(data))

1values = []
2for i in range(1000, 3001):
3    s = str(i)
4    if (int(s[0])%2 == 0) and (int(s[1])%2 == 0) and (int(s[2])%2 == 0) and (int(s[3])%2 == 0):
5        values.append(s)
6print ",".join(values)

 1lst = []
 2
 3for i in range(1000,3001):
 4    flag = 1
 5    for j in str(i):          # every integer number i is converted into string
 6        if ord(j)%2 != 0:     # ord returns ASCII value and j is every digit of i
 7            flag = 0          # flag becomes zero if any odd digit found
 8    if flag == 1:
 9        lst.append(str(i))    # i is stored in list as string
10
11print(",".join(lst))

1def check(element):
2    return all(ord(i)%2 == 0 for i in element)  # all returns True if all digits i is even in element
3
4lst = [str(i) for i in range(1000,3001)]        # creates list of all given numbers with string data type
5lst = list(filter(check,lst))                   # filter removes element from list if check condition fails
6print(",".join(lst))

1lst = [str(i) for i in range(1000,3001)]
2lst = list(filter(lambda i:all(ord(j)%2 == 0 for j in i), lst))   # using lambda to define function inside filter function
3print(",".join(lst))

1'''Solution by: nikitaMogilev
2'''
3# map() digits of each number with lambda function and check if all() of them even
4# str(num) gives us opportunity to iterate through number by map() and join()
5print(','.join([str(num) for num in range(1000, 3001) if all(map(lambda num: int(num) % 2 == 0, str(num)))]))

1hello world! 123

1LETTERS 10
2DIGITS 3

 1s = raw_input()
 2d = {"DIGITS":0, "LETTERS":0}
 3for c in s:
 4    if c.isdigit():
 5        d["DIGITS"]+=1
 6    elif c.isalpha():
 7        d["LETTERS"]+=1
 8    else:
 9        pass
10print "LETTERS", d["LETTERS"]
11print "DIGITS", d["DIGITS"]

 1word = input()
 2letter,digit = 0,0
 3
 4for i in word:
 5    if ('a'<=i and i<='z') or ('A'<=i and i<='Z'):
 6        letter+=1
 7    if '0'<=i and i<='9':
 8        digit+=1
 9
10print("LETTERS {0}\nDIGITS {1}".format(letter,digit))

1word = input()
2letter, digit = 0,0
3
4for i in word:
5    if i.isalpha(): # returns True if alphabet
6        letter += 1
7    elif i.isnumeric(): # returns True if numeric
8        digit += 1
9print(f"LETTERS {letter}\n{digits}") # two different types of formating method is shown in both solution

1''' Solution by: popomaticbubble
2'''
3import re
4
5input_string = input('> ')
6print()
7counter = {"LETTERS":len(re.findall("[a-zA-Z]", input_string)), "NUMBERS":len(re.findall("[0-9]", input_string))}
8
9print(counter)